The energy of a wave is related to its frequency by the following relationship:

E = h x `nu` `<span class="AM"><br> </span>`

Where E denotes the energy of the wave, `nu` is its frequency and h is the Planck's constant and has a value of 6.626 x 10^ (-34) J sec.

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The energy of a wave is related to its frequency by the following relationship:

E = h x `nu` `<span class="AM"><br> </span>`

Where E denotes the energy of the wave, `nu` is its frequency and h is the Planck's constant and has a value of 6.626 x 10^ (-34) J sec.

Substituting the value of energy (3.28 x 10^ (-19) J) and Planck's constant in the equation, we can solve for frequency as:

`nu` = E/h = {3.28 x 10^-19}/{6.626 x 10^-34}

= 4.95 x 10^14 Hz.

We can also calculate the wavelength of this wave, using the relationship between frequency and wavelength:

`nulambda` = c

Where, `nu` is the frequency and `lambda` is the wavelength of the wave. The constant c us the speed of light in vacuum and is equal to 3 x 10^8 m/s.

Hope this helps.

I assume that you are asking about electromagnetic radiation, which has a constant speed and a direct mathematical relationship between frequency and energy. That relationship is:

`E = h nu`

Where E = energy, `nu` = frequency and h = Planck's constant which has a value of

*h = 6.623 x10^(-34) Joules x seconds*

The energy per photon of radiation of this frequency is therefore:

E = 6.623 x 10^(-34) x 3.28 x 10^(-19) = 2.17 x 10^(-52)

A photon is a "quantum" unit of light energy. Planck's constant gives the energy per photon for a specific frequency.

The frequency of electromagnetic radiation is inversely proportional to wavelength. So the higher the frequency, the higher the energy and the shorter the wavelength, the higher the energy.